What will be the molarity of a solution, which contains 5.85 g of nacl(s) per 500 ml?

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Solution

The correct option is D 0.2mol L1
Calculating the number of moles of solute

Mass of solute (Nacl) = 5.85 g
Molar mass of solute (Nacl) = 58.5 g/mol

Number of moles of solute (Nacl) =
Mass of soluteMolar mass of solute(Nacl)=5.8558.5=0.1 mol

Molarity

To find molarity, formula used is:
Volume of the solution = 500 mL = 0.5 L

Molarity = number of moles of soluteVolume of solution (in L)

=0.1 mol0.5L=0.2 molL1

Thus, molarity of the given solution is 0.2mol L1


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Solution

Since, molarity (M) is calculated by following equation

Molarity=weight×1000molecular weight×volume(mL)

=5.85×100058.5×500=0.2mol L1

Note Molarity of solution depends upon temperature because volume of a solution is temperature dependent.


What is the molarity of the solution which contains 5.85 g of NaCl per 500 ml?

Thus, molarity of the given solution is 0.2 mol L−1.

What will be the molarity of a solution which contains 5.85 g of NaCl s per 500 ml solution ?( NA 23u CL 35.5u )?

Solution : `"Molarity"=("Moles of the solute")/("Volume of solution in L")=(5.85//58.5)/(0.500L)="0.2 mol L"^(-1)`. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

What will be the molarity of a solution which contains 2.925 g of NaCl s per 750 ml?

So, the molarity of a solution that has 29.25 grams of NaCl dissolved to make 1.5 L of a solution is 0.33 M. Hence, option (d) is correct.

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